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A has 4 elements, so n(A)=4 B has 6 elements, so n(B)=6 A U B = all elements which are in either A or B or both = {1,2,3,4,5,6,7,8) A U B has 8 elements so n(A U B) = 8 A ∩ B = all elements which A and B have in common = {2,4} A ∩ B has 2 elements, so n(A ∩ B) = 2 n(A U B) = n(A) n(B) n(A ∩ B) 8 = 4 6 2 8 = 10 2 8 = 8 So it's true (b) Make up your own two sets A and B, each8 9 Solutions In each of the these word searches, words are hidden horizontally, vertically, or diagonally, forwards or backwards Can you find all the words in the word lists?P R I O R I T Y D a t e 0 2 / 2 1 / 2 0 0 7

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If a,b,c,d are positive real numbers such that a/b < c/d, then show that a b < ac bd < b d Proof Since b and d are positive, we can multiply a/b < c/d to obtain ad −bc < 0 and hence bc−ad > 0 (Can you think of which properties we have used?Question A V (B Λ C) ⇔ (A V B) Λ (A V C)A Λ (B V C) ⇔ (A Λ B) V (A Λ C)Prove The Distributive Property Using Truth Tables This problem has been solved!Bsp5 Die beiden n × nMatrizen A, C in der folgenden Matrixgleichung seien invertierbar, X ist unbekannt A·X ·C = B Aufl¨osen nach X liefert die aquivalente Gleichung X = A−1·B·C−1 Falls auch noch B invertierbar ist, ist auch das Produkt X invertierbar und X−1 =(A−1 ·B ·C−1)−1 = C ·B−1 ·A siehe (R5) Bsp6 Die Inverse der Matrix A = 1 5 13 2 23 0 02 1 ist A−1 = 31

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In that case, the exponents add aman = amn but amdn cannot be further simplified, and aman 6= amn (d) Similarly for division am an = am−n 4 Roots Let a,b,m, and n be numbers (a) Remember that roots can always be viewed as fractional exponents n √ a = a n 1 With this point of view, we'll inherit117 212 < ` b a c r h j k ` h i l h l k ` _ – I j _ ^ k l Z \ e y \ Z i j _ g h k g Z k j _ ^ Z g Z Z a Z l Z g Z g _ g Z i j Z \ e y \ Z g b ( b a e t q · Also sei x aus A ∪ C, dann gilt x aus A oder x aus C 1 im Falle x aus A sagt die Vor, dann auch x aus B und dann also auch x aus B ∪ C, denn alle aus B sind in B ∪ C 2 im Falle x aus C ist natürlich auch x aus B ∪ C, denn alle aus C sind B ∪ C Die zweite Aussage kannst du so ähnlich beweisen Beantwortet 4 Nov 14 von

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Purplemath Venn diagrams can be used to express the logical (in the mathematical sense) relationships between various sets The following examples should help you understand the notation, terminology, and concepts relating Venn diagrams and set notation Let's say that our universe contains the numbers 1, 2, 3, and 4, so U = {1, 2, 3, 4}Let A be the set containing the(c) Two terms with exponents can only be multiplied if they share the same base; · This video is unavailable Watch Queue Queue Watch Queue Queue

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